pandas.Interval¶

class
pandas.
Interval
¶ Immutable object implementing an Interval, a bounded slicelike interval.
New in version 0.20.0.
Parameters:  left : orderable scalar
Left bound for the interval.
 right : orderable scalar
Right bound for the interval.
 closed : {‘right’, ‘left’, ‘both’, ‘neither’}, default ‘right’
Whether the interval is closed on the leftside, rightside, both or neither. See the Notes for more detailed explanation.
See also
IntervalIndex
 An Index of Interval objects that are all closed on the same side.
cut
 Convert continuous data into discrete bins (Categorical of Interval objects).
qcut
 Convert continuous data into bins (Categorical of Interval objects) based on quantiles.
Period
 Represents a period of time.
Notes
The parameters left and right must be from the same type, you must be able to compare them and they must satisfy
left <= right
.A closed interval (in mathematics denoted by square brackets) contains its endpoints, i.e. the closed interval
[0, 5]
is characterized by the conditions0 <= x <= 5
. This is whatclosed='both'
stands for. An open interval (in mathematics denoted by parentheses) does not contain its endpoints, i.e. the open interval(0, 5)
is characterized by the conditions0 < x < 5
. This is whatclosed='neither'
stands for. Intervals can also be halfopen or halfclosed, i.e.[0, 5)
is described by0 <= x < 5
(closed='left'
) and(0, 5]
is described by0 < x <= 5
(closed='right'
).Examples
It is possible to build Intervals of different types, like numeric ones:
>>> iv = pd.Interval(left=0, right=5) >>> iv Interval(0, 5, closed='right')
You can check if an element belongs to it
>>> 2.5 in iv True
You can test the bounds (
closed='right'
, so0 < x <= 5
):>>> 0 in iv False >>> 5 in iv True >>> 0.0001 in iv True
Calculate its length
>>> iv.length 5
You can operate with + and * over an Interval and the operation is applied to each of its bounds, so the result depends on the type of the bound elements
>>> shifted_iv = iv + 3 >>> shifted_iv Interval(3, 8, closed='right') >>> extended_iv = iv * 10.0 >>> extended_iv Interval(0.0, 50.0, closed='right')
To create a time interval you can use Timestamps as the bounds
>>> year_2017 = pd.Interval(pd.Timestamp('20170101 00:00:00'), ... pd.Timestamp('20180101 00:00:00'), ... closed='left') >>> pd.Timestamp('20170101 00:00') in year_2017 True >>> year_2017.length Timedelta('365 days 00:00:00')
And also you can create string intervals
>>> volume_1 = pd.Interval('Ant', 'Dog', closed='both') >>> 'Bee' in volume_1 True
Attributes
closed
Whether the interval is closed on the leftside, rightside, both or neither closed_left
Check if the interval is closed on the left side. closed_right
Check if the interval is closed on the right side. left
Left bound for the interval length
Return the length of the Interval mid
Return the midpoint of the Interval open_left
Check if the interval is open on the left side. open_right
Check if the interval is open on the right side. right
Right bound for the interval Methods
overlaps
()Check whether two Interval objects overlap.